x^2+0.3*x-1=0

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Solution for x^2+0.3*x-1=0 equation: 



x^2+0.3x-1=0

a = 1; b = 0.3; c = -1;
Δ = b2-4ac
Δ = 0.32-4·1·(-1)
Δ = 4.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.3)-\sqrt{4.09}}{2*1}=\frac{-0.3-\sqrt{4.09}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.3)+\sqrt{4.09}}{2*1}=\frac{-0.3+\sqrt{4.09}}{2}
$

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